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Quote from: Dinosaur on July 09, 2025, 09:10:19 PMI'm kinda confused. I bought the Tormek T-8 with the knife angle setter and the knife jigs. I follow the tuturials the same as on the YouTube videos.
But the thing is, their wheel is turning away from them and the knife edge. But my wheel is turning toward me toward the knife edge.
QuoteSo is there any way to reverse the spinning direction? Because obviously I can't sharpen knifes like this.
Quote from: tgbto on July 29, 2025, 07:59:17 AMQuote from: Herman Trivilino on July 28, 2025, 07:08:18 PMThe impedance is a complex number, containing both a real part and an imaginary part. For an ideal capacitor, the impedance is purely imaginary, with no real part.
But for a real capacitor, there is a real part. Quoting from Wikipedia:
"The magnitude of the impedance |Z| acts just like resistance, giving the drop in voltage amplitude across an impedance Z for a given current I."
My calculation gives the magnitude of the impedance as about 210 ohms.
That's why I said "loosely" speaking. I'm ignoring the imaginary part, which is, as you say, responsible for the phase shift.
Agreed, *but* you based your calculation on the capacitance only, meaning you assume an ideal capacitor.
QuoteSo you are not ignoring the imaginary part, you are dealing only with the imaginary part.
QuoteThe 210 ohms value you computed is a pure reactance, or said otherwise, no resistance at all.
To quote from the same wikipedia : "A pure reactance does not dissipate any power."
Quote from: tgbto on July 28, 2025, 09:01:21 AMJust kidding, they now sport sheaths...Quote from: BPalv on July 26, 2025, 09:54:20 PMOne note though, if you come over for dinner don't stick your hand in the knife drawer.
Do you mean you keep you ultra-sharp knives loose in a drawer![]()
Quote from: Herman Trivilino on July 28, 2025, 07:08:18 PMThe impedance is a complex number, containing both a real part and an imaginary part. For an ideal capacitor, the impedance is purely imaginary, with no real part.
But for a real capacitor, there is a real part. Quoting from Wikipedia:
"The magnitude of the impedance |Z| acts just like resistance, giving the drop in voltage amplitude across an impedance Z for a given current I."
My calculation gives the magnitude of the impedance as about 210 ohms.
That's why I said "loosely" speaking. I'm ignoring the imaginary part, which is, as you say, responsible for the phase shift.
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